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Please solve this question:-):-):-):-) |
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Answer» ong>Step-by-step explanation: When roots are given, equation in quadratic form x −(α+β)x+αβ=0 Here roots are (2α+3β) and (3α+2β) ∴x 2 −(2α+3β+3α+2β)x+(2α+3β)(3α+2β)=0 x 2 −5(α+β)x+6α 2 +4αβ+4αβ+6β 2 =0 f(x)=2X 2 −5x+7 α+β= 2 5
, αβ= 2 7
∴α 2 +β 2 =(α+β) 2 −2αβ = 4 25
−7= 4 −3
x 2 −5( 2 5
)x+6(− 4 3
)+13× 2 7
=0 ∴2x 2 −50x−18+182=0 2x 2 −50x+164=0 ∴x 2 −25x+82=0. |
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