1.

Please solve this question ❔❔​

Answer»

a^3+b^3+c^3-3abc=(a+b+c)[a^2+b^2+c^2-ab-bc-ca]

MULTIPLY and DIVIDE by 2 in RHS side

=2(a+b+c)/2[a^2+b^2+c^2-ab-bc-ca]

=(a+b+c)/2[2a^2+2b^2+2c^2-2ab-2bc-2ca]

=(a+b+c)/2[(a^2-2ab+b^2)+(b^2-2bc-c^2)+(c^2-2ca+a^2]

=(a+b+c)/2[(a-b)^2+(b-c)^2+(c-a)^2]


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