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Please solve this Projectile Question DONT SPAMM ! WARNING |
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Answer» Speed of the Ball = 5√5 m/sExplanation:Let say ball is thrown with speed = v m/sthen HORIZONTAL speed = vcosθ m/s& vertical speed = vsinθ m/sFinal Velocity = 10( i - j) m/s=> Horizontal Velocity = 10 m/s& vertical Velocity = -10 m/sHorizontal Speed will remain sameHence vcosθ = 10acceleration due to gravity will act on vertical velocitya = g = 10 m/sas ball is thrown upwards hence g will be - vetime taken to reach GROUND = 1.5 secfinal vertical velocity = initial vertcal veloicty + (-g) * times-10 = vsinθ - 10(1.5)=> -10 = vsinθ - 15=> vsinθ = 5vcosθ = 10 vsinθ = 5Squaring and adding both=> v²Cos²θ + v²Sin²θ = 10² + 5²=> v²(Cos²θ + Sin²θ) = 100 + 25=> v² = 125=> v = √125=> v = 5√5 m/sinitial Speed of the Ball 5√5 m/sLearn more:A ball thrown vertically up from the top of a tower reaches the ground ...brainly.in/question/8127453A ball is thrown up vertically returns to the thrower after 6 s . FIND: 1 ...brainly.in/question/9114082 |
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