Please solve it step by step ☺☺

1.	Please solve it step by step ☺☺
Answer» Given that A can COMPLETE a work in 10 DAYS. Work DONE by A in 1-day = (1/10). Given that B can complete the work in 12 days. Work done by B in 1-day = (1/12). Work done by A and B in 1-day = (1/10) + (1/12) = 11/60. *Work done by A and B in 3 days = (11/60) 3 = 11/20. Remaining work = (1 - 11/20) = 9/20. Now, 9/20 of the work completed by B in (12 * 9/20) = 108/20 days. Therefore, the total TIME taken = (108/20) + 3 = 168/20 = 42/5 = 8 (2/5) days. Hope this helps!**

Answer»

Given that A can COMPLETE a work in 10 DAYS.

Work DONE by A in 1-day = (1/10).

Given that B can complete the work in 12 days.

Work done by B in 1-day = (1/12).

Work done by A and B in 1-day = (1/10) + (1/12)

= 11/60.

Work done by A and B in 3 days = (11/60) * 3

= 11/20.

Remaining work = (1 - 11/20)

= 9/20.

Now,

9/20 of the work completed by B in (12 * 9/20) = 108/20 days.

Therefore, the total TIME taken = (108/20) + 3

= 168/20

= 42/5

= 8 (2/5) days.

Hope this helps!

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