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PLEASE SOLVE FAST IT VERY IMPORTANT!!DONT JOKE OR GIVE FALSE ANSWER.A cricket ball of mass 70g moving with a velocity of 0.5 m/s is stopped by a player in 0.5s. What is force applied by the player to stop the ball?

Answer» MASS of ball = 70G = 0.07 kg
vilocity of ball , U = 0.5 m/sec
time = 0.5 s
final vilocity of ball = 0 m/sec
force = mass (vilocity - u /time)
0.07 (0 - 0.5 /0.5)
-0.07 newton


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