Please solve and don't spam or write anything unnecessarily it is a re

1.	Please solve and don't spam or write anything unnecessarily it is a request ,question given below .
Answer» $\LARGE{ \underline{ \purple{ \sf{Required \: answer:}}}}$ GIVEN: $\rm{ \dfrac{ log(a) }{5} = \dfrac{ log(<klux>B</klux>) }{6} = \dfrac{ log(c) }{7} }$ We have to FIND the value of b² according to the above data. Let, $\rm{ \dfrac{ log(a) }{5} = \dfrac{ log(b) }{6} = \dfrac{ log(c) }{7} = k}$ Then, log a = 5K log b = 6k log c = 7k When the base of the logarithm is not mentioned, it is taken to be of base 10. a = $\rm{{10}^{5k} }$ b = $\rm{{10}^{6k} }$ c = $\rm{{10}^{5k} }$ We have to find the value of b² ⇛ $\rm{({{10}^{6k}})^{2} }$ ⇛ $\rm{{10}^{12k} }$ This can be written as, ⇛ $\rm{{10}^{5k + 7k} }$ ⇛ $\rm{{10}^{5k} }\times\rm{{10}^{7k} }$ ⇛ a × c Thus, the required value of b² is ac. And we are done...