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Answer» nitrate = 1g lead nitrate in 100g WATER. ( This is TECHNICALLY incorrect I know, but it is the simplest way of doing this problem) Solution = 10G Pb(NO3)2 in 1.0kg water Molar mass Pb(NO3)2 = 331.2200 g/MOL 10g Pb(NO3)2 = 10/331.22 = 0.030 mol in 1kg solvent solution is 0.03 molal Kf for water = 1.86°C /m.kg van't Hoff factor for Pb(NO3)2, i = 3 molality = 0.03m DELTA T = i*Kf*m delta t = 3*1.86*0.03 delta T = 0.168°C The solution will freeze at - 0.168°C. |
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