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Answer»

\frac{dr1}{dt}  = v1 =  3i + 8t \: j \\  \frac{dr2}{dt}  =v2 =  8t \: i + 3j \\ at \: t = 1 \\v1 = 3i + 8j \\ and \\ v2 = 8i + 3j  \\ therefore \\  \\ the \: relative \: velocity \: is \\ v1 - v2 =  - 5i + 5j \\ magnitude =  \sqrt{( - 5) {}^{2} + 5 {}^{2}  }  = 5 \sqrt{2}  \: m.s {}^{ - 1}



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