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Please jaldi full solve krna hai |
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Answer» CARNOT ENGINE OPTION A Explanation: ♣ THERMODYNAMICS ♥ ★ GIVEN ; ★ » Temperature of Source ( T¹ ) = 427°C ≈ 700 Kelvin ★» Temperature of Sink ( T² ) = 77° C ≈ 350 Kelvin ★★ EFFICIENCY OF CARNOT ENGINE ( ẞ ) = ?? _________ [ BY USING FORMULA ] __________ ★ ẞ = [ 1 - 350 / 700 ] » ẞ = [ 700 - 350 / 700 ] » ẞ = [ 350 / 700 ] = ( 1 / 2 ) ★ →[ %ẞ = 1 / 2 × 100 = 50 % ] ← ★ _________________________________________ ANSWER :- HENCE ,EFFICIENCY OF HEAT ENGINE IS ; ♣ ẞ = 50 % ♣ |
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