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Please help yaar it's urgent I have to this work in tuitionCh - Real NumbersClass 10thDon't even try to post irrevalent answers otherwise your 10 answers will be reported​

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Answer:

A.T.Q,

The NUMBER LEAVES 3 as REMAINDER.

So, 144 - 3 = 14

180 - 3 = 177

192 - 3 = 189

Now,

HCF of 141, 177 and 189 is 3.

And according to question It leaves remainder 3 in each case.

141 = 23 * 6 + 3

177 = 29 * 6 + 3

189 = 31 * 6 + 3

Thus, 6 is the number.

Hope it is helpful (•‿•)...


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