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The bus can OVERTAKE the car when their displacements are same and bus has more velocity.
velocity of bus initially =0=u(bus).
acceleration of bus=1ms^-2.
s = ut + \frac{1}{2} a {t}^{2}
s=0(t)+1/2(1)t^2...(1)this is equation of DISPLACEMENT of bus whereas initial velocity of car=5m/s and acceleration of car =0 ms^-2.
So equation of displacement of car is s=5(t)+1/2(0)t^2...(2)
equate (1)and(2). we get 5t=1/2t^2 =>10t=t^2=> t=10 seconds . now calculate the displacement from equation(1)=>s=5t=5(10)=50 m. velocity of bus can be CALCULATING the below formula
v=u+at here u=0 m/s and a=1ms^-2. v=0+1(10)=10 m/s. answers for
first part =>50 m.
second part=>10m/s.


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