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Please help me to find the answer for this qn.... |
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Answer» Step-by-step EXPLANATION: In ΔACQ AQ² = AC² + QC² AQ² = AC² + (BC/2)² AQ² = AC² + BC²/4 .............(1) In ΔBPC BP² = BC² + PC² BP² = BC² + (AC/2)² BP² = BC² + AC²/4 ...........(2) Adding (1) and (2) AQ² + BP² = AC² + BC² + AC²/4 + BC²/4 4(AQ² + BP²) = 5AC² + 5BC² 4(AQ² + BP²) = 5(AC² + BC²) 4(AQ² + BP²) = 5(AB²) |
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