Please help me solve this.... pleaseeeeeee

1.	Please help me solve this.... pleaseeeeeee
Answer» Given that, cos x = - 4/5 COSINE is NEGATIVE in second and third quadrant but with accordance to given constraints, x WOULD lie in second quadrant where SINE is positive. We know that, sin²x + cos²x = 1 $\longrightarrow$ sin²x + 16/25 = 1 $\longrightarrow$ sin²x = 9/25 $\longrightarrow$ sin x = 3/5 (Second Quadrant) Thus, sin2x $\longrightarrow$ 2 × 3/5 × -4/5 $\longrightarrow$ -2 × 12/25 $\longrightarrow$ -24/25

Answer»

Given that,

cos x = - 4/5

COSINE is NEGATIVE in second and third quadrant but with accordance to given constraints, x WOULD lie in second quadrant where SINE is positive.

We know that,

sin²x + cos²x = 1

$\longrightarrow$ sin²x + 16/25 = 1

$\longrightarrow$ sin²x = 9/25

$\longrightarrow$ sin x = 3/5 (Second Quadrant)

Thus,

sin2x

$\longrightarrow$ 2 × 3/5 × -4/5

$\longrightarrow$ -2 × 12/25

$\longrightarrow$ -24/25

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