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PLEASE HELP ME IN THIS QUESTION!!!!!​

Answer»
{2}^{ - m} \times \frac{1}{ {2}^{m} } = \frac{1}{4} \\ {2}^{ - m} \times {2}^{ - m} = {2}^{ - 2} \\ \\ {2}^{ - 2m} = {2}^{ - 2} \\ - 2m = - 2 \\ m = 1
\frac{1}{14}( ( { {4}^{m} )}^{ \frac{1}{2} } + {( \frac{1}{ {5}^{m} } )}^{ - 1} ) \\ \frac{1}{14} ( {4}^{ \frac{1}{2} } + 5) \\ \frac{1}{14} (2 + 5) \\ \frac{1}{14} \times 7 \\ \frac{1}{2}


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