1.

Please help! find length of DE!

Answer»

Given:-

• angleD = 60

• EF = 4√3

To find:-

• DE = ?

Solution:-

As we know that,

As we know that

\tan( \alpha ) = \frac{perpendicular}{base}

\tan(60) = \sqrt{3}

So,

= > \tan(60) = \frac{4 \sqrt{3} }{x} \\ = > \sqrt{3} = \frac{4 \sqrt{3} }{x } \\ = > x = \frac{4 \sqrt{3} }{ \sqrt{3} } \\ = > x = 4

Hence the value of DE = 4

Hope its help uh❤


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