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Please help A sphere of man 40kg is placed at a distance 0.9m from a sphere of mans 60kg If the two spheres attract each other with a force of 0.02mgf find the value of G |
| Answer» TION:Distance (G)=20cm=0.2mMass (M 1 )=40kg Mass (m 2 )=15kgForce (F)=0.1 milligram wt =0.1×10 −3 ×980 dyne =98×10 −3 dyne =98×10 −8 N =9.8×10 −9 NF= R 2 GM 1 M 2 G= M 1 M 2 FK 2 = 40×159.8×10 −7 ×0.2×0.2 = 4×1598×2×2 × 10×10×10×1010 −7 =6.5×10 −11 m 2 /kss 2 | |