1.

Please give step by step explaination

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ANSWER:

for two VECTORS A and B .

VEC{A}+vec{B}=vec{C}

|a+b|=|c|

or, \bf{\sqrt{A^2+B^2+2ABcos\theta}=C}or, \bf{A^2+B^2+2ABcos\theta=C^2}given, A - B = Cso, {c}^2 = {(A -B)}^2 using it in above expression.or, \bf{A^2+B^2+2ABcos\theta=(A-B)^2}or, A^2+B^2+2ABcos\theta=A^2+B^2- 2ABor, 2ABcos\theta=2ABor, cos\theta=1=cos0^{\circ}

since theeta is 0

option 1 is correct

Step-by-step explanation:


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