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Please do it fast tomorrow is my exam. |
Answer» Answer :-Speed of train , u = 90 km/h = 90 × 5/18 = 25 m/s acceleration , a = -0.5 m/s² Use FORMULA, v = u + at Finally train will be rest so, final velocity, v = 0 0 = 25 - 0.5t 25 = 0.5t ⇒t = 50 sec Again, use formula, S = UT + 1/2at² Where S is distance TRAVELLED before stop S = 25 × 50 - 1/2 × 0.5 × 50² = 1250 - 1/2 × 0.5 × 2500 = 1250 - 625 = 625 m Hence, distance travelled = 625m and time taken = 50 sec |
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