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Please answerIf a and b are positive real numbers then √ab=​

Answer» ONG>Answer:

If a and b are positive real numbers, then a+b≥2ab−−√.

I know how to do the direct proof, but in this case, I want to try PROVING it by contradiction. I have tried MANIPULATING the inequality a+b<2ab−−√ after making the assumption that a,b>0 to GET a contadiction a,b≤0.

a+ba2−2ab+b2(a−b)2<2ab−−√<0<0,

Step-by-step explanation:

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