e!!!!Given:A car travels at a SPEED of 60km/h for 0.52h, of 30km/h for the next 0.24h, and then at 70km/h for the next 0.71h.We need to find the average speed of the car.Let us consider the first caseA car travels at a speed of 60 km/h for a time of 0.52 hWe KNOW that Speed = distance / time = 30km/hHence Distance = Speed X TimeDistance=60 x 0.52 = 31.2 km ————–(i)Now, in the second case, A car travels at a speed of 30 km/h for a time of 0.24 HR.We know that speed = distance / time = 30 km/hrDistance = Speed X TimeDistance=30 × 0.24 = 7.2 km ———–(ii)Here in the THIRD case, A car travels at a speed of 70km/h for a time of 0.71 hr.We know that speed = distance / time = 70km/hrHence Distance = Speed X Time=70 × 0.71 hr speed = distance / time = 70km/hrDistance = 70 × 0.71 = 49.7 km ———–(iii)Combining all the EQUATIONS (i), (ii) and (iii) and adding we get,Total distance travelled= (31.2 + 7.2 + 49.7) km = 88.1 km .Total time taken = (0.52 + 0.24 + 0.71) hr = 1.47 hr .Average speed = Total distance travelled / Total time taken= (88.1/1.47) km /hrHence, average speed = 59.9 km/hrHope it will help you!!!!!