AB and DE is PREPENDICULAR to BC So,AB is parallel to DE BY THEOREM,IF a line is parallel to one side of. a triangle then it divides the other two SIDES in same ratio so, AD/CD=BE/EC adding 1 both sides 1+AD/CD=1+BE/CE (CD+AD)/CD=(CE+BE)/CE AC/CD=BC/CE ABC ~DEC AB/DE=AC/CD 6/4=15/CD CD=15×2/3=10cm ratio of AREAS =6²/4²=36/16=9/4