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Please answer the given questions :1. In Triangle ABC AD is perpendicular to BC. (AD)2= BD X CD. prove that AB2+AC2=(BD +CD) 2. |
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Answer» Answer: In the GIVEN Fig., AD ⊥ BC. PROVE that AB2 + CD2 = BD2 + AC2. In right ∆ADC. by PYTHAGORAS Theorem, AC2 = AD2 + CD2 ...(i) In right ∆ADB, by Pythagoras Theorem, AB2 = AD2 + BD2 ...(ii) Subtracting (i) from (ii), we get AB2 - AC2 = BD2 - CD2 ⇒ AB2 + CD2 = BD2 + AC2 Hence PROVED. |
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