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Please answer the given questions :1. In Triangle ABC AD is perpendicular to BC. (AD)2= BD X CD. prove that AB2+AC2=(BD +CD) 2.​

Answer»

Answer:

In the GIVEN Fig., AD ⊥ BC. PROVE that AB2 + CD2 = BD2 + AC2.

In right ∆ADC. by PYTHAGORAS Theorem,

AC2 = AD2 + CD2 ...(i)

In right ∆ADB, by Pythagoras Theorem,

AB2 = AD2 + BD2 ...(ii)

Subtracting (i) from (ii), we get

AB2 - AC2 = BD2 - CD2

⇒ AB2 + CD2 = BD2 + AC2 Hence PROVED.



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