1.

Please answer the above question

Answer»

In MECHANICS problems like these, we’ll usually use one of the following 5 equations:

Refer the figure::

Since we don’t have a time, we can eliminate equations 1, 2, 3, and 5.

For EQUATION 4, we need an initial velocity (u), a FINAL velocity (v), and an acceleration (a). We’re given an initial velocity of 30 ms^-1 and the acceleration due to gravity is -9.81 ms^-2. At the maximum height, the velocity will be 0 ms^-1 — therefore the final velocity is 0 ms^-1.

Solving for s (DISPLACEMENT — which will give us the heigh):

v^2 = u^2 + 2as

v^2 - u^2 = 2as

(v^2 - u^2) / 2a = s

s = ((0 m/s)^2 - (30 m/s)^2) / 2(-9.81 m/s^2) = -900 / -19.62 = 45.9 m


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