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PLEASE ANSWER QUESTION 1 |
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Answer» Step-by-step explanation: p(1)= 0 p(3)= 0 p(-2)=0 so 3;-2;1 are the ZEROS of the cubic polynomial let S=1;K=3;p=-2 general equation is ax3+bx2+cx+d s+k+p=-b/a 2=-b/a b/a=2 product =SPK = -d =6 sp+pk+sk=-5 so the equation is X3-2X2-5X+6 |
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