Please answer q.no. 5 immediately

1.	Please answer q.no. 5 immediately
Answer» ANSWER: average velocity is 7m/s avg acceleration is 4m/s Explanation: s=6-3t+2t2 PUTTING 1 in t s=6-3×1+2×1 s1=5 now putting t=4 similary by solving s2=26 now avg velocity= s2-s1/t2-t1 =26-5/4-1 =21/3 =7m/s now for acceleration differentiat the equation ds/dt=d/dt×6-d/dt×3t+d/dt×2t2 v= -3+4t putting 1 In t v1=1 similarly putting 4 in t V2=13 now avg acceleration is V2-v1/t2-t1 solving avg acceleration is 4m/S2

Answer»

ANSWER:

average velocity is 7m/s

avg acceleration is 4m/s

Explanation:

s=6-3t+2t2

PUTTING 1 in t

s=6-3×1+2×1

s1=5

now putting t=4

similary by solving

s2=26

now

avg velocity= s2-s1/t2-t1

=26-5/4-1

=21/3

=7m/s

now for acceleration differentiat the equation

ds/dt=d/dt×6-d/dt×3t+d/dt×2t2

v= -3+4t

putting 1 In t

v1=1

similarly putting 4 in t

V2=13

now

avg acceleration is V2-v1/t2-t1

solving

avg acceleration is 4m/S2

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Please answer q.no. 5 immediately

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