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Answer» Magnitude of electric field intensity = 3 × 10³ N/CSide of the square = 10cm = 0.1mTo find : (a) The flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane. (B) The flux through the same square if the normal to its plane makes a 60° ANGLE with the X- axis.Solution :(a) The plane of square is parallel to the yz plane. So, angle between the plane and electric field is 0°Flux through the plane is given by,where,E DENOTES Electric field intensityA denotes area of squareby substituting all the given VALUES in the equation,Thus, the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane is 30Nm²/C.(b) Here, the plane makes an angle of 60° with the x-axis so, the angle between them will be 60°Applying the same formula,thus, the flux through the same square if the normal to its plane makes a 60° angle with the x- axis is 15Nm²/C. |
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