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| Answer» BULLET Let the initial velocity be u₁Let the FINAL velocity be v₁For the blockLet the initial velocity be u₂Let the final velocity be v₂Let the mass of the bullet be m₁Let the mass of the BLOCK be m₂Formula and concept :By Law of Conservation of Energy :Sum of initial momentum = sum of final momentum .m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂We know that v₁ = v₂ .Let v₁ = v₂ = vSo : m₁ u₁ + m₂ u₂ = m₁ v + m₂ vConversions m₁ = 10 g = 0.01 kgm₂ = 900 g = 0.9 kgu₁ = 400 m/su₂ = 0 m/sCalculate the velocity m₁ u₁ + m₂ u₂ = m₁ v + m₂ v= > 0.01 × 400 + 0.9 × 0 = v ( 0.01 + 0.9 )= > 4 + 0 = v × 0.91= > 0.91 v = 4= > v = 4 / 0.91= > v = 4.395ANSWER:The velocity is 4.4 m/s | |