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Please answer me no. 12 part 1

Answer»
log(m + n) =  log(m )  +  log(n)  \\  log(m + n)  =  log(mn)  \\ taking \: antilog \: both \: sides \\  \\ m + n = mn \\ m - mn =  - n \\ m(1 - n) =  - n \\ m =  \frac{ - n}{1 - n}  \\ m =  \frac{n}{n - 1}
HOPE this will HELP you.


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