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please answer it urgently please the perimeter of an isoscles triangle is 42 cm and its base is (3/2) times each of the equal sides. find the length of each side of the triangle, area of the triangle and the height of the triangle.

Answer»

Let X is one side of triangle
42=x+x+3/2x
42=2x+3/2x
42=2+3/2x
42=7/2x
42×2/7=x
x=2×6
x=12
now12 is one side
2 side is 24
then BASE = 42-24 =18
half of base is 9
by USING Pythagoras
12^2=9^2+height^2
height^2=114-81
height ^2=33
height=√33



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