1.

Please answer fast.. find the atea of shaded region​

Answer»

Answer:

A ( ∆ ABC ) = 1/2 × BASE × height

= 1/2 × 48 × 20

[ draw a perpendicular to BC . by Pythagoras theorem we get (52)² - (48)²= (20)² . so height of triangle is 20 CM ]

A ( ∆ ABC ) = 48 × 10

A (∆ ABC ) = 480 cm²

now

by Pythagoras theorem,

in RIGHT angled ∆ ADB

AD²+ DB² = AB²

12² + 16² = AB²

144+256 = AB²

400 = AB²

AB = 20 cm

also

A( ∆ ADB ) = 1/2 × base × height

= 1/2 × 16 × 12

= 16 × 6

= 96 cm²

area of shaded portion = A( ∆ ABC ) - A(∆ ADB )

= 480 - 96

= 384 cm²

fol low. karo yaar

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