Saved Bookmarks
| 1. |
Please answer 21st question fastly it's urgent. |
|
Answer» Step-by-step explanation: 1.Draw a LINE BC parallel to AD Draw a perpendicular line BE on DF ABCD is a parallelogram. BC=AD=25cm CD=AB=60cm CF=77-CD=17cm For Δ BCF perimeter of triangle=(25+26+17)/2 =68/2=34 By Heron's Formula of triangle=√s(s-a)(s-b)(s-c) =√34(34-25)(34-26)(34-17) =204cm² Now AREA of ΔBCF=1/2xbase X height =1/2 BExCF204cm² =1/2x BEx17BE =408/17 =24cm Area of Trapezium =1/2(AB+DF)xBE =1/2(60+77)x24 =1644cm² Read more on Brainly.in - brainly.in/question/127574#readmore |
|