1.

pK_(a) of acetic acid is 4.74. The concentration of CH_(3)COONa is 0.01 M. The pH of CH_(3)COONa is

Answer»

8.37
4.37
4.74
0.474

Solution :`pH = 7 + (1)/(2)[pK_(a) + log C] = 7 + (1)/(2)[4.74 + log 10^(-2)]`
`= 7 + (1)/(2)[4.74 -2] = 7+ (2.74)/(2) = 8.37`


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