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Pipes A and B can fill a tank in 12 minutes and 15 minutes, respectively. The tank when full can be emptied by pipe C in x minutes. When all the three pipes are opened simultaneously, the tank is full in 10 minutes. The value of x is:1. 242. 183. 154. 20 |
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Answer» Correct Answer - Option 4 : 20 Given: A can-do 1 unit work = 1/12 minutes B can do 1 unit work = 1/15 minutes C can do 1 unit work = - 1/x minutes Together they can fill the tank = 1/10 minutes Formula used: Total work = Efficiency × days Solutions: ⇒ 1/total days = 1/A + 1/B - 1/C ⇒ 1/10 = 1/12 + 1/15 - 1/x ⇒ 1/x = 1/12 + 1/15 - 1/10 ⇒ 1/x = (5 + 4 - 6)/60 ⇒ 1/x = 3/60 ⇒ x = 20 ∴ The value of x is 20. |
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