1.

Photon is quantum of radiation with energy E = hv, where v is frequency and his Planck's constant. The dimensions of h are the same as that of

Answer»

linear impulse
angular impulse
linear MOMENTUM
angular momentum

Solution :For E=hv
`[h]=([E])/([v])=([ML^(2)T^(-2)])/([T^(-1)]=[M^(1)L^(2)T^(-1)]`
For (A), DIMENSION of linear impulse = Dimension of momentum`[M^(1)L^(1)T^(-1)]`
For (B) and (D),
Dimensions of angular impulse = Dimension of angular momentum =
`[M^(1)L^(-2)T^(-1)]`
This is EQUAL to the dimension of Planck.s constant h.


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