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Phosphorous pentachloride dissociates as follows (in a closed reaction vessel): `PCI_(5)(g)hArrPCI_(3)(g)+CI_(2)(g)` If the total pressure at equilibrium on the reaction mixture is P and the degree of dissociation of `PCI_(5)` is x, the partial pressure of `PCI_(3)` will beA. `((x)/(x+1))P`B. `((x)/(1-x))P`C. `((2x)/(1-x))P`D. `((x)/(x-1))P` |
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Answer» Correct Answer - A `{:(,PCl_(5)(g),hArrPCl_(3)(g),+Cl_(2)(g)),("Initial (moles)",I,0,0),("Change (moles)",1-x,+x,+x),("Equilibrium (moles)",1-x,x,x):}` Total moles `=n_(PCl_(5))+n_(PCl_(3))+n_(Cl_(2))` `=(1-x)+(x)+(x)` `=1+x` Partial pressure of `PCl_(3)` `=("Mole fraction of" PCl_(3))xx("Total pressure of" PCl_(3))` `=((x)/(1+x))P` |
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