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फलन`f(x)` जिसके लिए ` f(x) {: {(x^(2),x !=1),(2,x=1):}` दिखाइए कि ` lim _( x to 1) f( x) = 1 ` |
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Answer» ` lim_ ( x to 1+0) f(x) = lim _ ( x to 1 + 0) f( 1 + h) = lim _ ( h to 0) ( 1 + h)^(2) = 1 ` और `lim_ ( x to 1 - 0 ) f ( x) = lim _ ( x to 1 - 0 ) f ( 1- h) = lim _ ( h - 0) ( 1- h)^(2) = 1 ` ` :. lim _ ( x to 1 + 0 ) f( x) = lim _ ( x to 1 -0) f ( x) = 1 ` अतः ` lim _( x to 1) f(x) = 1 ` |
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