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pH of a saturated solution fo magnesium hydroxide in water at `298K` is 10. The solubility of the hydroxide in water at 298 K isA. `5xx10^(-5)molL^(-1)`B. `5xx10^(-12)molL^(-1)`C. `1xx10^(-4)molL^(-1)`D. `1xx10^(-10)molL^(-1)` |
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Answer» Correct Answer - A `Mg(OH)_(2)iffMg^(2+)+2OH^(-)` pH of `Mg(OH)_(2)` solution is 10 `becausepOH=4` So `[OH^(-)]=10^(-4)` `[OH^(-)]=2xx"solubility"` `because "solubility"=(10^(-4))/(2)=0.5xx10^(-4)=5xx10^(-5)molL^(-1)` |
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