Ph−ClMg−−−−−→dry ether CO2/H+,H2O−−−−−−−� – InterviewSolution

1.	Ph−ClMg−−−−−→dry ether CO2/H+,H2O−−−−−−−−−→ SOCl2−−−−→ i. CH2N2−−−−−−−−→ii. Ag2O, H2O Number of O atom(s) in the final product is:
Answer» $P h - C l M g - ---- \to dry ether C O_{2} / H^{+}, H_{2} O - -------- \to S O C l_{2} - --- \to i . C H_{2} N_{2} - ------- \to i i . A g_{2} O, H_{2} O$ Number of $O$ atom(s) in the final product is:

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