pH calculation upon dilution of a strong acid solution is generally do

1.	pH calculation upon dilution of a strong acid solution is generally done by equating nH+ in original solution and diluted solution. However, if strong acid solution is very dilute, then H+ from water are also to be considered. Take log3.7 = 0.568 and answer the following questions. A litre solution of pH = 6 (solution of a strong acid) is added to the 73 litre of water. What is the pH of resulting solution? Neglect the common ion effect on H2O.
Answer» pH calculation upon dilution of a strong acid solution is generally done by equating $n_{H^{+}}$ in original solution and diluted solution. However, if strong acid solution is very dilute, then $H^{+}$ from water are also to be considered. Take log3.7 = 0.568 and answer the following questions. A litre solution of pH = 6 (solution of a strong acid) is added to the $\frac{7}{3}$ litre of water. What is the pH of resulting solution? Neglect the common ion effect on $H_{2} O$ .

pH calculation upon dilution of a strong acid solution is generally done by equating nH+ in original solution and diluted solution. However, if strong acid solution is very dilute, then H+ from water are also to be considered. Take log3.7 = 0.568 and answer the following questions. A litre solution of pH = 6 (solution of a strong acid) is added to the 73 litre of water. What is the pH of resulting solution? Neglect the common ion effect on H2O.

Answer»

pH calculation upon dilution of a strong acid solution is generally done by equating $n_{H^{+}}$ in original solution and diluted solution. However, if strong acid solution is very dilute, then $H^{+}$ from water are also to be considered. Take log3.7 = 0.568 and answer the following questions.

A litre solution of pH = 6 (solution of a strong acid) is added to the $\frac{7}{3}$ litre of water. What is the pH of resulting solution? Neglect the common ion effect on $H_{2} O$ .

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