1.

Perimeter of a triangle with vertices (0,0), (6,0), (0 8) is24441434​

Answer»

Answer:

24

Step-by-step explanation:

LET the triangle be ABC where

  A(0,0) ;  B(6,0) ;  C(0,8)

AB=\sqrt[]{(6-0)^{2} +(0-0)^{2} }=6

BC=\sqrt{(0-6)^{2} +(8-0)^{2} } =\sqrt{36+64} =\sqrt{100} =10

CA=\sqrt{(0-0)^{2}+(0-8)^{2} } =8

Perimeter of triangle= AB + BC + CA = 6 + 10 + 8 = 24



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