1.

Perimeter of a triangle with vertices (0,0), (6,0), (0 8) ​

Answer»

Step-by-step explanation:

let A(0,0) B(6,0) C(0,8)

AB = √{(0-6)^2 + (0-0)^2}

= √ (-6)^2

= 6 units

BC = √{(6-0)^2 + (0-8)^2}

= √{(6)^2 + -8)^2}

= √36 + 64

= √100

= 10 units

AC = √{(0-0)^2 + (0-8)^2}

= √(-8)^2

= 8 units

perimeter = AB + BC + AC

= 6 + 10 + 8

= 24 units


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