Per unes 783, ind is bar and3. Find the area of the triangle whose sid

1.	Per unes 783, ind is bar and3. Find the area of the triangle whose sides are 42 cm, cand 20 cmlength. Hence, find the height corresponding to the longest
Answer» ${\red{\overbrace{\underbrace{\bf{\bigstar Solution : \:\bigstar}}}}}\\$ $\text{[math]}$ a = 42cm b = 42 cm c = 20CM using herons formula $\longrightarrow$ $s \longrightarrow <klux>SEMI</klux> perimeter$ semi perimeter = 42 + 42 + 20cm/2 = 104cm/2 = 52cm AREA = $\sqrt{s (s - a)(s - b)(s - c)}$ area = $\sqrt{ 52(52- 42)(52 - 42)(52 - 20)}$ area = $\sqrt{ 52 × 10 × 10 × 32}$ area = $\sqrt{ 166,400}$ 1/2 × base × height = $407.92$ 20cm × height = $407.92 × 2$ 20cm × height = $815.84$ height = 815.84/20 height = 40.79cm ${\orange{\underline{\underline{\bf{\bigstar\:\: height : 40.79cm \:\:\bigstar}}}}}\\$ $\text{[math]}$ area of triangle = 1/2 × base × height = 1/2 × 20cm × 40.79cm = 1/2 × 807.90cm² = 403.95cm² ${\green{\boxed{\boxed{\bf{ area\:of\: triangle : {403.95cm}^{2}}}}}}\\$