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Particles of masses 1 g, 2 g, 3 g, ... 100g, are kept at the marks 1 cm, 2 cm, 3 cm, ..... 100 cm respectively on a meter scale. Find the moment of inertia of the system of particles about a perpendicular bisector of the meter scale. |
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Answer» SOLUTION :`[1xx49^(2)+2xx48^(2)+3xx47^(2)+.........49xx1^(2)+52xx2^(2)+......98xx48^(2)+99xx49^(2)+100xx50^(2)]10^(-7)` `=100p[50^(2)+49^(2)+48^(2)+.......+1^(2)]xx10^(-7)` `=10^(-5)xx(1)/(6)xx50xx51xx101=0.431kgm^(2)` |
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