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Particle of masses `m, 2m,3m,…,nm` grams are placed on the same line at distance `l,2l,3l,…..,nl cm` from a fixed point. The distance of centre of mass of the particles from the fixed point in centimeters is :A. `((2n+1)l)/3`B. `l/(n+1)`C. `(n(n^(2)+l)l)/2`D. `(2l)/(n(n^(2)+l)l)` |
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Answer» Correct Answer - A `x_(cm)=(Summx)/(Summ)=((1^(2)+2^(2)+3^(2)+...+n^(2))l)/((1+2+3+...++n))` |
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