Particle is projected with speed 5√2 m/s at an angle of projection 45∘ from horizontal. At maximum height it breaks in two identical particle, velocity of one particle is zero, find time (in sec) when first part strikes the ground after explosion. Take g=10 m/s2

Particle is projected with speed 5√2 m/s at an angle of projection

1.	Particle is projected with speed 5√2 m/s at an angle of projection 45∘ from horizontal. At maximum height it breaks in two identical particle, velocity of one particle is zero, find time (in sec) when first part strikes the ground after explosion. Take g=10 m/s2
Answer» Particle is projected with speed $5 \sqrt{2} m/s$ at an angle of projection $45^{\circ}$ from horizontal. At maximum height it breaks in two identical particle, velocity of one particle is zero, find time (in sec) when first part strikes the ground after explosion. Take $g = 10 {m/s}^{2}$