Particle A of mass m1 moving with velocity (√3^i+^j) ms−1 collides with another partice B of mass m2 which is at rest initially. Let →V1 and →V2 be the velocities of particles A and B after collision respectively. If m1=2m2 and after collision →V1=(^i+√3^j)ms−1, the angle between →V1 and →V2 is :

Particle A of mass m1 moving with velocity (√3^i+^j) ms−1 collide

1.	Particle A of mass m1 moving with velocity (√3^i+^j) ms−1 collides with another partice B of mass m2 which is at rest initially. Let →V1 and →V2 be the velocities of particles A and B after collision respectively. If m1=2m2 and after collision →V1=(^i+√3^j)ms−1, the angle between →V1 and →V2 is :
Answer» Particle $A$ of mass $m_{1}$ moving with velocity $(\sqrt{3}^i +^j) m s^{- 1}$ collides with another partice $B$ of mass $m_{2}$ which is at rest initially. Let $_{1}$ and $_{2}$ be the velocities of particles $A$ and $B$ after collision respectively. If $m_{1} = 2 m_{2}$ and after collision $_{1} = (^i + \sqrt{3}^j) m s^{- 1},$ the angle between $_{1}$ and $_{2}$ is :

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