Page No.DateThe height ofa Particulartole is increasingat therate of 1

1.	Page No.DateThe height ofa Particulartole is increasingat therate of 10 cm per month.What wouldbe height of the toueafter5 yearsif its present height islom?
Answer» Answer: Present Height - 10m If the rate increases 10 cm er month then: 1 month = 10 cm 12 months ( 1 YEAR) -> 10x12=120 cm 5 years = 120 x 5 = 600 cm Convert cm into m 1 cm = 0.01 m 600 cm = 0.01 x 600 = 6 m present height = 10 m Add 5 years = 10 m + 6 m = 16 m The answer is 16 m Step-by-step explanation: here's the answer of your questions please follow me up

Page No.DateThe height ofa Particulartole is increasingat therate of 10 cm per month.What wouldbe height of the toueafter5 yearsif its present height islom?

Answer»

Answer:

Present Height - 10m

If the rate increases 10 cm er month then:

1 month = 10 cm

12 months ( 1 YEAR) -> 10x12=120 cm

5 years = 120 x 5 = 600 cm

Convert cm into m

1 cm = 0.01 m

600 cm = 0.01 x 600 = 6 m

present height = 10 m

Add 5 years = 10 m + 6 m = 16 m

The answer is 16 m

Step-by-step explanation:

here's the answer of your questions

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Page No.DateThe height ofa Particulartole is increasingat therate of 10 cm per month.What wouldbe height of the toueafter5 yearsif its present height islom?​

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Page No.DateThe height ofa Particulartole is increasingat therate of 10 cm per month.What wouldbe height of the toueafter5 yearsif its present height islom?