PAGE NO.DATEIf the velocity of the car changes from 10m/s to 40 m/s in

1.	PAGE NO.DATEIf the velocity of the car changes from 10m/s to 40 m/s in 5 seconds what will be the acceleration of the car
Answer» Answer: Let’s review the 4 fundamental KINEMATIC equations of MOTION for constant acceleration (SUGGEST you commit these to MEMORY): s = ut + ½at^2 …. (1) v^2 = u^2 + 2as …. (2) v = u + at …. (3) s = (u + v)t/2 …. (4) where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time. In this case, we know u = 10m/s, v = 50m/s, t = 10s and we want to find a, so we use equation (3) v = u + at 50 = 10 + 10t, so t = (50 – 10)/10 = 4m/s^2 The acceleration is 4m/s^2. hope it will be useful please follow me and mark MI as brainleast

PAGE NO.DATEIf the velocity of the car changes from 10m/s to 40 m/s in 5 seconds what will be the acceleration of the car

Answer»

Answer:

Let’s review the 4 fundamental KINEMATIC equations of MOTION for constant acceleration (SUGGEST you commit these to MEMORY):

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we know u = 10m/s, v = 50m/s, t = 10s and we want to find a, so we use equation (3)

v = u + at

50 = 10 + 10t, so t = (50 – 10)/10 = 4m/s^2

The acceleration is 4m/s^2.

hope it will be useful

please follow me and mark MI as brainleast

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