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Page No:Date:1Three pieces of timber 42 m, 49 m and 63m longhave to be divided into planks of the same lengthWhat is the greatest possible length of each plank?How many planks are farmed? |
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Answer» HCF of 42,49,63 = 7 1st plank i.e 42/7 = 6 2nd plank i.e 49/7 = 7 3rd plank i.e 63/7 = 9 Planks formed are = 6 + 7 + 9 = 22 |
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