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Page No:Date:1Three pieces of timber 42 m, 49 m and 63m longhave to be divided into planks of the same lengthWhat is the greatest possible length of each plank?How many planks are farmed?

Answer»

HCF of 42,49,63 = 7

1st plank i.e 42/7 = 6

2nd plank i.e 49/7 = 7

3rd plank i.e 63/7 = 9

Planks formed are = 6 + 7 + 9 = 22



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