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PaceDate s

Answer»

2sec^2x-sec^4x-2cosec^2x+cosec^4x=(1-tan^8x)/tan^4x.

=sec^2x(2-sec^2x)-cosec^2x(2-cosec^2x) .

put sec^2x=1+tan^2x , cosec^2x =1+cot^2x.

=(1+tan^2x)(2–1-tan^2x)-(1+cot^2x)(2–1-cot^2x).

=(1+tan^2x)(1-tan^2x)-(1+cot^2x)(1-ccot^2x).

=1-tan^4x-1+cot^4x.

=cot^4x-tan^4x.

=1/tan^4x -tan^4x.

=(1- tan^8x)/tan^4x. , Proved.



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